K 10 9
K 9 8
K 8 6 2
Q 10 9
7 3 2
A 7 3
J 8 7 4 2
Q J 8 4
A 10 7 4
J 10 9 4
A 6 5
Q J 5 3
A K 5 3
Against 3 NT
, West led the ♠ 7
, which went to the 10,
jack, and ace.
Declarer then led a heart to the king and ace, and East exited with
the ♦ J
. This was duck all around, and East continued with
a low diamond to the queen and West's ace. West continued with his
last diamond, won in dummy, declarer pitching a spade from hand.
Declarer then cashed his two hearts and three rounds of clubs at this
Declarer has found nothing breaking. Still, on the ♣ K
, East is
squeezed in three suits. If he parts with the a spade, declarer gets two spade
tricks. If he parts with a diamond, dummy's diamond is good. And if he
parts with a heart, declarer's heart is good.
This is a triple squeeze. Note that the count has not been rectified.
Sadly, our declarer decided that West led the ♠ 7
from a doubleton,
and therefore thought the end position was:
When East parted with a spade, declarer led his last heart, which declarer
hoped would force East to lead spades into the ♠ K-10
. As the cards were,
however, East cashed the ♦ 9
, setting the contract.
Might West's spade lead be from a doubleton? It certainly might, but
West is know to have started with only two hearts. If he held two
small hearts and two small spades, and he chose to lead a major,
about half of the time he would lead a heart. But with
three spades and two hearts, he will almost always choose the spade.
This is a subtle form of restricted choice, and I think it leads
to the conclusion that West is more likely to have started
with three spades.
The spade lead was the only one with a chance to set this contract.
All other leads give declarer his ninth trick.